Question

sin 0 -cos 0 +1/
sin 0 + cos 0 -1 =1 / sec 0 - tan 0
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Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

LHS=(sin0-cos0+1) / (sin0+cos0-1)

dividing by cos0 with both numerator and denominator

=,(sin0/cos0-cos0/cos0+1,/cos0) / (sin0/cos0+cos0/cos0-1/cos0

=(tan0+ sec0-1) / (tan0-sec0+1)

multiply (tan0-sec0) with both numerator and denominator

=(tan0+sec0-1) ( tan0-sec0) / (tan0-sec0+1) (tan0-sec0)

=[(tan^0-sec^0) - ( tan0-sec0)] / (tan0-sec0+1)(tan0-sec0)

=(-1-tan0+sec0) / (tan0-sec0+1)( tan0- sec0). [hence, sec^0-tan^0= 1]

= -1/(tan0-sec0)

= 1 / ( sec0-tan0)= RHS

HOPE THIS WILL HELP YOU

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