Question

(sin 0 + cos 0)2 + (sin 0 - cos 0)2​

Answer 1

Answer:

0

Step-by-step explanation:

sin0=0 ,cos0=1

put this value in expression we get 0

0 is answer

Answer 2

Involved formula :-

sin²θ + cos²θ = 1

(a + b)² = a² + b² + 2ab

Calculation :-

(sinθ + cosθ)² + (sinθ - cosθ)²

= sin²θ + cos²θ + 2sinθcosθ + sin²θ + cos²θ - 2sinθcosθ

= 1 + 1

= 2

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