Math, asked by jayramakshitainfra, 4 months ago

(sin 0 + cos 0)2 + (sin 0 - cos 0)?​

Answers

Answered by ashupm
1

Answer:

(sinθ−cosθ)2+(8nθ+cosθ)2

(sinθ−cosθ)(sinθ+cosθ)=(1−sin2θ)+(1+sin2θ)=sin2θ−cos2θ

=2sin2θ−1+sin2θ=22sin2θ−1

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