Question

sin 0 + cos 0
(3) If tan 0= 1, then find the values of
sec 0 + cosec 09​

Answer 1

Step-by-step explanation:

here is your solution.

Answer 2

Answer:

tan 0 = 1

tan0=tan45° ( tan45°=1)

0=45°

sin¢+cos¢/sec¢+cosec¢

= sin45°+cos45/sec45+cosec45

=1/√2 + 1/√2 / √2+√2

=√2 /2√2

=1/2

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