Math, asked by ca303957, 10 months ago

sin 0 cos (90° - 0) + cos e sin (90° - 0)

Answers

Answered by Anonymous

2

Answer:

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Answered by royalelena541

5

Answer:

1

Step-by-step explanation:

SinО cos (90⁰-0) + cosΟ sin (90⁰-0)

sin O cos ( $90^{0}-0$ ) +cos O sin ( $90^{0}-1$ )

cancel $90^{0} -1$ 0n the both side

sinO cos +cos O sin

sinO (sin) +cos O(cos)

$sin^{2} O +cos^{2} O$

1 (ans) [ $sin^{2}+cos^{2} =1 ]$

Hope it will help you

Plzz.. mark my answer as brainliest

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