(sin 0 + cosec 0)2 + (cos 0 + sec 0) find the value
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1
Answer:
3
Step-by-step explanation:
=(sin 0+cosec 0)2+(cos 0+sec 0). (cosec 0=1-sin 0
sec 0 = 1-cos 0)
=(sin 0+1-sin 0)2+(cos 0+1- cos 0)
both sin 0 and both cos 0 cancelled
=(1×2)+1
=2+1
=3
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