Question

Sin^-1 (1-x)-2sin^-1 x=pi/2

Answer 1

Answer:

Hey!!

Step-by-step explanation:

let  sin^-1  (1-x) = A  ,   So  Sin A  = 1-x

let  Sin^-1 x = B,     So Sin B = x 

Given  A - 2 * B = π/2

           A  - π/2  = 2B

          Cos (A - π/2)  = Cos (2 B)

          Sin A =  1 - 2 Sin² B 

          1 - x   = 1 - 2 x² 

          2 x² - x = 0

          x = 0 or   x = 1/2

      

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Answer 2

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Ans:✍️✍️✍️✍️✍️✍️

Given,

$a - 2 \times b = \frac{\pi}{2}$

$a - \frac{\pi}{2} = 2b$

$cos \: a - \frac{\pi}{2} = cos \: 2b$

$sin \: a = 1 - 2 {sin}^{2} \: b$


$1 - x = 1 - 2 {x}^{2}$


${2x}^{2} - x = 0$


so,

$x = 0$


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