sin^-1 (√3-1/2√2) Find the principal value
Answers
Answer:
π/12
Step-by-step explanation:
let us assume that θ=sin^-1 ((√3-1) / 2√2)
=>sin θ= ((√3-1) / 2√2)
=>θ=π/12
=>sin^-1 ((√3-1) / 2√2) = π/12
some additional information:
*inverse trigonometric functions are one-one and onto functions (bijective function).thus,they are also invertible functions.
*although trigonometric functions are many-one and into functions but by restricting the domain of it ,we can make it an invertible functions.
*these restriced domains of the inverse trigonometric functions are called principal value branch and the range is called principal range.unless stated,we assume that the value belong to principal value branch only.
*inverse trigonometric is not just a formula oriented chapter but it requires a lot of understanding.