Question

(sin/1+cos ) + ( 1+cos÷sin) = 2 cosec

Answer 1

Answer:

sin/1+cos ) + ( 1+cos÷sin) = 2 cosecs

Step-by-step explanation:

LHS = sin(sin) + (1+cos)(1+cos)/[(sin)(1+cos)]

= sin^2 + (1+cos)^2/)/[(sin)(1+cos)]

= [sin^2 +cos^2 + 1 +2cos]/[(sin)(1+cos)]

= [1 + 1 + 2cos ]/[(sin)(1+cos)]

= 2(1 + cos ) / [(sin)(1+cos)]

= 2/ sin = 2 cosec = RHS

Note :

sin^2 +cos^2 = 1