Math, asked by surendradeval920, 4 hours ago

sin/1-cos + cos/1-tan = cos+sin​

Answers

Answered by satyajeetmalla004
0

Answer:

LHS

= cosA/1-(sinA/cosA) + sinA/1-(cosA/sinA)

=cosA/(cosA-sinA)/cosA+sinA/(sinA-cosA)/sinA

=cosA ×cosA/cosA-sinA+(sinA×sinA)/sinA-cosA

=cos^2 A/cosA-sinA + sin^2 A/sinA-cosA

=cos^2 A-sin^2 A/cosA-sinA

=(cosA+sinA) (cosA-sinA)/cosA-sinA

=cosA+sinA

Step-by-step explanation:

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