Sin/1+cos+sin/1-cos=2cosec
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Answered by
0
Answer:
L.H.S. =
sinA
1+cosA
+
1+cosA
sinA
=
sinA(1+cosA)
(1+cosA)(1+cosA)+sinAsinA
=
(1+cosA)sinA
(1+cosA)
2
+sin
2
A
=
(1+cosA)sinA
1+cos
2
A+2cosA+sin
2
A
=
(1+cosA)sinA
1+2cosA+1
=
(1+cosA)sinA
2+2cosA
=
(1+cosA)sinA
2(1+cosA)
=2
sinA
1
=2cosecA
=R.H.S
Hence proved.
hope this helps you
Answered by
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Answer:
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