Question

sin^-1(cosx) how to find it's derivative​

Answer 1

Answer:-

Given,

$= > \bold{y=sin { }^{ - 1} (cosx)} \\ = > \bold{y = sin {}^{ - 1}sin (\frac{\pi}{2} - x) } \\ = > \bold{y = \frac{\pi}{2} - x }$

Now, differentiating both sides with respect to "x", we get,

$= > \bold{\boxed{\frac{dy}{dx} = 1}}$

Imp. to know:-

It is because, we know that derivative of every only "x" is 1.