Math, asked by farhan4695, 1 year ago

sin ( 1+ tan) + cos(1+cos) =sec+ cosec​

Answers

Answered by Anonymous
3

sin (1 + tan) + cos (1 + cot) = sec + cosec

Left Hand Side

= sin (1 + tan) + cos (1 + 1 ÷ tan)

= sin (1 + tan) + cos (1 + tan) ÷ tan

= (1 + tan)(sin + cos ÷ tan)

= (1 + tan)(sin × tan + cos) ÷ tan

= (1 + tan)(sin^2 ÷ cos + cos) ÷ tan

= (1 + tan)(sin^2 + cos^2) ÷ tan × cos

= (1 + tan) ÷ tan × cos

= (1 ÷ tan × cos) + tan ÷ tan × cos

= ( cot ÷ cos) + (1 ÷ cos)

= cosec + sec [LHS = RHS] (PROVED)


Anonymous: Hope this is helpful :)
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