Math, asked by mits07009, 2 months ago

sinθ(1+tanθ)+cosθ(1+cotθ)=secθ +cosecθ ​

Attachments:

Answers

Answered by Nightfury234
1

Answer:

L:H:S = sinθ(1+tanθ)+cosθ(1+cotθ)

=sinθ(1+

cosθ

sinθ

)+cosθ(1+

sinθ

cosθ

)

=sinθ

cosθ

(sinθ+cosθ)

+cosθ

sinθ

(sinθ+cosθ)

=(sinθ+cosθ)(

cosθ

sinθ

+

sinθ

cosθ

)

=

sinθcosθ

(sinθ+cosθ)

(sin

2

θ+cos

2

θ)

=(

cosθ

1

+

sinθ

1

)

=secθ+cosecθ=R:H:S (proved)

Attachments:
Similar questions