sin^-1(x^2+y^2) = tan^-1(y/n) + c represents a circle then find the centre and radius of circle
Answers
Answered by
1
Step-by-step explanation:
x=
1+t
2
2a(1−t
2
)
and y=
1+t
2
4 a t
let,t=tanθ
x=2a(
1+tan
2
θ
1−tan
2
θ
) ⇒x=2acos2θ
y=
1+tan
2
θ
4atanθ
⇒y=2a sin2θ
∴
4a
2
x
2
+
4a
2
y
2
=1
x
2
+y
2
=4a
2
So, the radius of circle is 2a.
Hope by seeing this you can do the sum yourself ☺☺
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