Question

sin-1
x + cos^3x, xe[-1, 1] =
TT
(
A)
O
(B)
2
2π
(D)
(C)
n​

Answer 1

Step-by-step explanation:

Identity (II)

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$$\huge\fbox\pink{Answer}$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$$\huge\fbox\pink{Answer}$$(3a - 4b) (3a - 4b)$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$$\huge\fbox\pink{Answer}$$(3a - 4b) (3a - 4b)$Using identity (II)

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$$\huge\fbox\pink{Answer}$$(3a - 4b) (3a - 4b)$Using identity (II)$(3a) ^{2} - 2 \times 3a \times 4b + (4b) ^{2}$

Identity (II)$9 a^{2} - 24ab \: + 16b^{2}$$(a - b) ^{2}$$= a^{2} - 2ab + b ^{2}$$\huge\fbox\pink{Answer}$$(3a - 4b) (3a - 4b)$Using identity (II)$(3a) ^{2} - 2 \times 3a \times 4b + (4b) ^{2}$$9a^{2} - 24ab + 16b ^{2}$