Question

sin^-1 x = pi/7 then cos^-1 x=​

Answer 1

Step-by-step explanation:

Questions

${ \sin }^{ - 1} x = \frac{\pi}{7} then \: find \: { \cos}^{ - 1} x$

Solutions

Formula

${ \sin }^{ - 1} x + { \cos }^{ - 1} x = \frac{\pi}{2}$

Given

${ \sin }^{ - 1} x = \frac{\pi}{7}$

on subtracting both (LHS and RHS) side by π/2 we get

$- \frac{\pi}{2} + { \sin }^{ - 1} x = \frac{\pi}{7} - \frac{\pi}{2} \\ { \cos }^{ - 1} x = \frac{(2\pi - 7\pi)}{14} \\ { \cos}^{ - 1} x = - \frac{5\pi}{14}$