Math, asked by kumar492989, 11 days ago

sin^-1(x√x) find dy/dx​

Answers

Answered by skmuffiskmuffi
0

Answer:

2/√x√(1 – x)

(2) -2/√x√(1 – x)

(3) 1/2√x√(1 – x)

(4) 1/√(1 – x)

Solution:

Given y = sin-1√x

Differentiate w.r.t.x

dy/dx = [1/√(1-(√x)2)]×1/2√x

= 1/2√x√(1 – x)

Hence option (3) is the answer.

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Answered by sheffroy
0

Answer:

sure

Step-by-step explanation:

Given y = sin-1√x

Differentiate w.r.t.x

dy/dx = [1/√(1-(√x)2)]×1/2√x

= 1/2√x√(1 – x)

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