sin^-1(x√x) find dy/dx
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Answer:
2/√x√(1 – x)
(2) -2/√x√(1 – x)
(3) 1/2√x√(1 – x)
(4) 1/√(1 – x)
Solution:
Given y = sin-1√x
Differentiate w.r.t.x
dy/dx = [1/√(1-(√x)2)]×1/2√x
= 1/2√x√(1 – x)
Hence option (3) is the answer.
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Answer:
sure
Step-by-step explanation:
Given y = sin-1√x
Differentiate w.r.t.x
dy/dx = [1/√(1-(√x)2)]×1/2√x
= 1/2√x√(1 – x)
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