Question

Sin 10 +Sin20 .... + Sin 360=?​

Answer 1

Step-by-step explanation:

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(sin10° + sin350°) + (sin20° + sin340°) + (sin30° + sin330°) + ....+ (sin170° + sin190°) + (sin180° + sin360°)

This forms to 18 pairs and each pair is zero.

sin10° + sin350° = sin10° + sin(360 - 10) = sin10° - sin10° = 0

So every term becomes zero.

Answer 2

Answer:

0

Step-by-step explanation:

Sin 10 +Sin20 .... + Sin 360

= sin 10 + sin 20 +sin 30 + ... + sin 330+ sin 350 + sin 360

=(sin 10+ sin (360-10))+ (sin 20+ sin (360-20))+(sin 30+ sin (360-30))+...+ (sin 180+ sin (360-180))

= (sin 10 - sin 10)+  (sin 20 - sin 20)+  (sin 30 - sin 30)+ .....+   (sin 180 - sin 180)

=0