Question

sin 105° + cos 105º = cos 45º
answer only when you know it ??​

Answer 1

Please refer to the attached solution

So here is what I did in solution:-

1. Break sin105° and cos105° into smaller angles

2. Now divide and multiple whole equation by √(a² + b²) i.e., √2.

What is a and b?

Our general equation is acosx + bsinx hence in equation sin75° - cos75°, a and b are 1 and - 1 respectively so √(a² + b²) is √[1² + (- 1)²] = √2.

3. Now simply use sinAcosB - cosAsinB = sin(A - B)

Tell me if you have any problem in this solution ;)

Answer 2

Answer:

hope it helped u :)

Step-by-step explanation:

Mark as brainliest answer :)