Question

sin(-11π/3) tan(35π/6​

Answer 1

Answer:

2/√3

Step-by-step explanation:

{sin(-11π/3)tan(35π/6)sec(-7π/3)}/{cos(5π/4)cosec(7π/4)cos(17π/6)}

therefore,

[sin(-11π/3) = √3/2 ]

[tan(35π/6) = -1/√3]

[sec(-7π/3) = sec(π/3) = 2]

[cos(5π/4) = cos(π + π/4) = - cos(π/4) = -1/√2]

[cosec(7π/4) = cosec(2π - π/4)

= -cosec(π/4) = -√2]

[cos(17π/6) = cos(2π + 5π/6)

= cos(π + π/6) = -cos(π/6) = -√3/2]

now ,

{sin(-11π/3)tan(35π/6)sec(-7π/3)}/{cos(5π/4)cosec(7π/4)cos(17π/6)}

=> {(√3/2)(-1/√3)(2)}/{(-1/√2)(-√2)(-√3/2)}

=> -1/{-√3/2}

=> 2/√3

I HOPE IT'S HELP YOU

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