sin 120° cos 150-cos240 sin330 =
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Answer:
Hey let's solve this problem
Step-by-step explanation:
(sin70
0
cos10
0
−cos70
0
sin10
0
)
=sin(70
0
+10
0
) [ ∵ (sinAcosB−cosAsinB)=sin(A−B) ]
=sin60
0
=
2
3
.
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