Sin (-1230°)-cos{(2n+1)π+π\4}
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0
Answer:
We'll assume integer
n
and the first argument is degrees; the second radians. That's a lot of assumptions to do this silly problem.
sin
(
−
1230
∘
)
−
cos
(
(
2
n
+
1
)
π
+
π
3
)
=
sin
(
−
1230
∘
+
3
×
360
∘
)
−
cos
(
2
π
n
+
4
π
3
)
=
sin
(
−
150
∘
)
−
cos
(
4
π
3
)
=
−
sin
150
∘
−
cos
240
∘
=
−
sin
30
∘
−
cos
120
∘
=
−
sin
30
∘
+
cos
60
∘
=
−
sin
30
∘
+
sin
30
∘
=
0
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