Math, asked by prashantpoudyal2004, 7 months ago

sin 135º cos 210°tan 240°cot 300° sec 330°













Answers

Answered by kamalkandpal480
3

√2 sin135 cos210 tan240 cot300 sec330 sin135 = sin(180-45) = sin45 = 1/√2 cos210 = cos(180+30) = -cos30 = -√3/2 tan240 ...

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