Question

sin(π/15)+ sin (4π/15)- sin( 14π/15)- sin (11π/15)= 0​

Answer 1

Step-by-step explanation:

which is the required ans.

Om SAI RAM.

Answer 2

Answer with Step-by-step explanation:

LHS

$sin\frac{\pi}{15}+sin\frac{4\pi}{15}-sin\frac{14\pi}{15}-sin\frac{11\pi}{15}$

$sin(\frac{\pi}{15})+sin(\frac{4\pi}{15})-sin(\pi-\frac{\pi}{15})-sin(\pi-\frac{4\pi}{15})$

We know that

$sin(\pi-\theta)=sin\theta$

Using the formula

$sin(\frac{\pi}{15})+sin(\frac{4\pi}{15})-sin\frac{\pi}{15}-sin\frac{4\pi}{15}$

$(sin\frac{\pi}{15}-sin\frac{\pi}{15})+(sin\frac{4\pi}{15}-sin\frac{4\pi}{15})$

$0-0=0$

LHS =RHS

Hence, proved.

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