sin 15° cos 15°-cos 75° sin 75°
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Answer:
given,
sin15 cos15 - cos75sin75
we know that,
sin(90-A)=cosA, cos(90-A)=SinA
therefore,
=sin(90-75)cos15 - cos75 Sin(90-15)
=cos75 cos15 - cos75 cos15
=0
hope it's helpful for you
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