sin? 15º+sin75°/
Cos 36° + cos54°
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Answer:
Explanation:
we can also write in this way
sin15+sin75 (numerator part)
apply sinA+sinB fomula
sinA+sinB=2sin(A+B/2)cos(A-B/2)
let A=15 and B=75
2sin(15+75/2)cos(15-75/2)
2sin(90/2)cos(60/2) cos(-a)=cosa
2sin45cos30
2*1/root2*root3/2
root(2/3) equation 1
we know the value of cos 36= root5+1/2
cos 54= root(10-2root5)/4
cos 36+cos54
root5+1/2 + root(10-2root5)/4
4root2/3/2root5+root(10-2roo5)+2 equation 2
divide 1and 2 equation
we will get the final answer as 2root5+root(10-2root5)+2/4
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