sin 15ºcos 75° +cos 15º sin 75°
Find the value of sec? 10º – cot80° + –
cos O sin (90° - 0) + sin 0 cos (90° - 0)
Answers
Answered by
2
Answer:
1.389
Step-by-step explanation:
sin 15° cos 75° + cos 15° sin 75°
= sin (15+75)°
= sin 90°= 1
sec 10° - cot 80° + cos 0°sin (90-0)°+
sin 0° cos (90-0)°
=( 1-cos 80°)/sin 80° + 1+ 0
= {2 (sin 40°)^2}/2sin 40°cos 40° + 1
= tan 40° +1
= 0.839+1 = 1.839
I hope it is correct because the question is too vague.
Similar questions