Question

sin 160° cos 110° + sin 250° cos 340° +tan110 tan340<br />​

Answer 1

Answer:

0

Step-by-step explanation:

sin(180-20)cos(90+20)+sin(270-20)cos(360-20)+tan(90+20)tan(360-20

= sin 20(-sin20)+(-cos20)cos20+(_cot20)(-tan20)

=-(sin^2 20+cos^2 20)+1

=-1+1

=0