sin 18 ÷ cos 72 + root 3 { tan 10 tan 30 tan 40 tan 50 tan 80 }
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4
Answer:
Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]
=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]
=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]
=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]
=1 + √3 [tan 30]
=1 + √3 [1/√3]
=1 + 1 = 2
Answered by
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Answer:
Sin18°/cos(90-18)+Root3 {tan10.1/v3.tan40.tan(90-40).tan(90-10)
Sin18/sin18+Root3 {1/v3.tan10.tan40.cot40.cot10}
1+1=2
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