Math, asked by Ankurajpandey, 1 year ago

sin 18 degree by cos 72 degree

Answers

Answered by saurav01234567890
3
sin 18 degree by cos 72 degree....HERE U GO,

Sin18/cos72

sin18/sin(90-72)

sin18/cos18

tan18

Aanchal001: then how will u solve
Aanchal001: oh
Aanchal001: ok
Aanchal001: tq
Answered by Anonymous
2

Answer:

»» 1

Step-by-step explanation:

sin18°/cos72°

= cos(90° - 18)/ cos 72°

{ °•° cos 90°- θ = sin θ }

= cos 72°/cos 72°

= 1

\bf\red{Thanks}

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