sin 18 degree by cos 72 degree
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sin 18 degree by cos 72 degree....HERE U GO,
Sin18/cos72
sin18/sin(90-72)
sin18/cos18
tan18
Sin18/cos72
sin18/sin(90-72)
sin18/cos18
tan18
Aanchal001:
then how will u solve
Answered by
2
Answer:
»» 1
Step-by-step explanation:
sin18°/cos72°
= cos(90° - 18)/ cos 72°
{ °•° cos 90°- θ = sin θ }
= cos 72°/cos 72°
= 1
☺
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