Math, asked by amitmal9107, 11 months ago

sin(-1845),cos(2190)tan(3645)sec(480)cosec(870)

Answers

Answered by amitnrw
8

Given :   sin(-1845),cos(2190) , tan(3645), sec(480), cosec(870)

To find :  Values

Solution:

sin(-1845)  =  - sin(1845)

= -sin( 1800 + 45)

=-Sin(360 * 5 + 45)

= -Sin45

= -1/√2

cos(2190)

=Cos(2160 + 30)

= Cos 30

= √3 / 2

tan(3645)

= tan ( 3600 + 45)

= tan 45

= 1

sec(480)

= Sec(360 + 120)

= sec 120

= - 2

cosec(870)

= Cosec(720 + 150)

= Cosec(150)

= 2

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Answered by sahil1393
0

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