Question

sin^-1x + sin^-1(2x) = π/3​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

sin^-1x+sin^-1 2x =π/3

Solution :

Let's sin^-1x=A and sin^-1 2x =B

Then , sinA=x and sinB = 2x

Because,A+B =π/3

B=π/3-A

Putting sin both sides

SinB=Sin(π/3-A)

SinB= sinπ/3cosA-cosπ/3sinA

SinB=√3/2×cosA- 1/2 sinA

SinB=√3/2×cos(sin^-1x)-1/2sin(sin^-1x)

Sin(sin^-1 2x)= √3/2√(1-sin^2sin^-1x)-1/2×X

2x =√3/2√(1-x^2)-1/2×x

4x+x=√3√(1-x^2)

25x^2=3-3x^2

28x^2=3

x^2=3/28

x=√3/(2√7)

ANSWER