Math, asked by Maajid2578, 1 year ago

sin^2-(1+√3)sinx.cosx+√3cos2x=0

Answers

Answered by aman34711

0

putting x= 0°
sin^2(0°)-(1+√3)sin0°cos0°+√3cos2(0°)
sin0°=0
cos0°=1
0-(1+√3)×0×1 + (√3 × 1)
0-0+√3
√3 ans

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