Math, asked by sangitaksingh7890, 1 year ago

sin^2 10° + sin^2 80° / sec^2 20° - cot^2 70° - 3tan80°tan50°tan45°tan10°tan40°

Answers

Answered by RajeshMane

0

I don't know what to do

takshakpatil9: Yeah true !!

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