(sin^2 22+sin^2 68/cos^2 22+cos^2 68)+sin^2 63+os^2 63 sin^2 27
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Answered by
111
sin^2 22+sin^2 68/cos^2 22+cos^2 68+sin^2 63+sin^2 27
sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227
=1/1+1
=2
so in this question you have two know
sinA =cos (90-A)
cosA=sin (90-A)
sin^2 A+cos^2 A=1
sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227
=1/1+1
=2
so in this question you have two know
sinA =cos (90-A)
cosA=sin (90-A)
sin^2 A+cos^2 A=1
Answered by
59
Answer:
The following identities are applied to get the answer
SinA=cos(90-A)
CosA=sin(90-A)
sin^A+cos^A=1
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