Math, asked by devasoorya, 1 year ago

(sin^2 22+sin^2 68/cos^2 22+cos^2 68)+sin^2 63+os^2 63 sin^2 27

Answers

Answered by Sarth45
111
sin^2 22+sin^2 68/cos^2 22+cos^2 68+sin^2 63+sin^2 27

sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227

=1/1+1

=2

so in this question you have two know

sinA =cos (90-A)

cosA=sin (90-A)

sin^2 A+cos^2 A=1
Answered by mohammadanas92
59

Answer:

The following identities are applied to get the answer

SinA=cos(90-A)

CosA=sin(90-A)

sin^A+cos^A=1

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