Question

{(sin^2 22° +sin^2 68°)/cos^2 22° + cos²68°}+ sin^2 63º+cos 63°.sin 27°​

Please answer correctly it else u will be reported!

Answer 1

Answer:

sin^2 68 = cos^2 22

cos^2 68 = sin^2 22

using sin^2A + cos^2A = 1,

(sin^2 22° +cos^2 22°) =1

similar for the rest of the problem....

final answer is 1

Answer 2

Answer:

2

Step-by-step explanation:

1. sin^2 22° + sin^2(90-22)°/cos^2 22°+cos^2(90-68)° + sin^2 63°+ cos63°.sin27°
2. sin^2 22°+cos^2 22°/cos^2 22°+sin^2 22° +{sin^2 63° + cos63°.sin(90-63)°}
3. 1/1 + {sin^2 63° + (cos 63°.cos63°)}
4. 1/1 + (sin^2 63°+cos^2 63°)
5. 1+1=2
6. Ans÷ 2