Question

sin^2 ((2pi)/3) + cos((3pi)/4) - 3/2 * tan((7pi)/3)

Answer 1

Step-by-step explanation:

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>(1/sqrt2)^2+(1/sqrt2)^2(-1/sqrt2)^2+(-1/sqrt2)^2

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>(1/sqrt2)^2+(1/sqrt2)^2(-1/sqrt2)^2+(-1/sqrt2)^2<br>

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>(1/sqrt2)^2+(1/sqrt2)^2(-1/sqrt2)^2+(-1/sqrt2)^2<br>1/2+1/2+1/2+1/2

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>(1/sqrt2)^2+(1/sqrt2)^2(-1/sqrt2)^2+(-1/sqrt2)^2<br>1/2+1/2+1/2+1/2<br>

sin^2pi/4+sin^2(3pi)/4+sin^2(5pi)/4+sin^2(7pi)/4<br>(1/sqrt2)^2+(1/sqrt2)^2(-1/sqrt2)^2+(-1/sqrt2)^2<br>1/2+1/2+1/2+1/2<br>2

Answer 2

Answer:

Value is 3/4 -1/√2 -3√3/2

Step-by-step explanation:

sin²2π/3 + cos3π/4 - 3/2 *tan7π/3

=( sin(π- π/3))² +cos(π- π/4) -3/2 *tan(2π +π/3)

= (sin π/3)² - cos π/4 -3/2 *tan π/3

=( √3/2)²- 1/√2 -3/2*√3

= 3/4 -1/√2 -3√3/2