Question

sin^2 30° + cos^2 30°/sec^2 57°- tan^2 57°=1

Please solve it​

Answer 1

Answer:

1

Step-by-step explanation:

${sin}^{2} 30 + {cos}^{2} 30 \div {sec}^{2} 57 - {tan}^{2} 57 \\ = 1 - {cos}^{2} 30 + {cos}^{2} 30 \div 1 + {tan}^{2} 57 - {tan}^{2} 57 \\ = 1 \div 1 \\ = 1$