Question

Sin^2 35°+Sin^2 55°+Sec Theeta ×Cosec (90- Theeta)-Tan Theeta×Cot(90-Theeta)÷Tan 10° ×Tan 20°×Tan 30° ×Tan 70°× Tan 80°

Answer 1

Answer:

2√3

Step-by-step explanation:

in denominator except tan30 and other will get cancelled bcz tan80 changes into cot (10) tan 30 is left so its 1/√3

so numerator multiplied by √3

sin^2 55 changes into cos^2 35

cosec 90-theeta chande to sec theeta cot changes to tan theeta

sin cos one pair

sec tan another pair

so (1+1)×√3

2√3