Question

Sin^2((π/4)-x)+cos ^2((π/4)+x)

Answer 1

sin*2x+ cos*2x =1

(sinπ/4cosx-cosπ/4sina)*2. +(cosπ/4cosx-sinπ/4sina)*2

(1/√2cosx-1/√2sinx)*2+(1/√2cosx-1/√2sina)*2

(1/2cosx*2-1/2sinx*2-2/4cosx sinx)+(1/2cos*2x+1/2sinx*2-2/4cosxsinx)

cos*2x+sin*2x-cosxsinx

1-cosxsinx