Math, asked by IraDwivedi, 6 months ago

sin^2 45+cos (33-theta)-sin(57+theta)

Answers

Answered by lalitnit

0

Answer:

sin^2 45+cos (33-theta)-sin(57+theta)

= 1/2 + sin (90 - 33 + theta) - sin(57+theta)

= 1/2 + sin (57 + theta) - sin(57+theta)

= 1/2 + 0

= 1/2

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