sin^2 45+cos (33-theta)-sin(57+theta)
Answers
Answered by
0
Answer:
sin^2 45+cos (33-theta)-sin(57+theta)
= 1/2 + sin (90 - 33 + theta) - sin(57+theta)
= 1/2 + sin (57 + theta) - sin(57+theta)
= 1/2 + 0
= 1/2
Similar questions
Computer Science,
1 month ago
Biology,
1 month ago
Science,
3 months ago
Math,
8 months ago
Math,
8 months ago