Math, asked by naveenkumars260, 1 year ago

sin^2 45 degree + cos^2 45 degree - tan^2 45 degree =?

Answers

Answered by Mankuthemonkey01
1
We know that


sin45° =
 \frac{1}{ \sqrt{2} }
cos45° =
 \frac{1}{ \sqrt{2} }
and tan45° =
1


So sin²45° =
( \frac{1}{ \sqrt{2} } ) {}^{2}  =  \frac{1}{2}
cos²45° =
( \frac{1}{ \sqrt{2} } ) {}^{2}  =  \frac{1}{2}
and tan²45° =
 {1}^{2}  = 1


So,

sin²45° + cos²45° - tan²45°

= 1/2 + 1/2 - 1

=> 2/2 - 1

=> 1 - 1

= 0

So the value of

sin²45° + cos²45° - tan²45°

= 0


Hope it helps dear friend ☺️✌️

naveenkumars260: Thanks guru
Mankuthemonkey01: xD Welcome bhaiya
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