Question

sin 2 45 - tau2 45 - sec2 45​

Answer 1

Answer:

$\boxed{\bf \frac{-5}{2} }$

Explanation:

$sin \ 45 ^0 = \frac{1}{\sqrt{2}} \\\\tan \ 45^0 =1\\\\sec \ 45^0 =\frac{1}{cos 45^0} =\sqrt{2} \\\\\\ => sin^245^0 -tan^245^0-sec^245^0 \\\\=> (\frac{1}{\sqrt{2}})^2-1^2-\sqrt{2}^{2} \\\\=>\frac{1}{2} -1-2\\\\=>\frac{1}{2} -3 \\\\=>\frac{1-6}{2} \\\\=>\frac{-5}{2}$

Answer 2

→ sin² 45° - tan² 45° - sec² 45°

$→ { \big \{1/( \sqrt{2}) \big\}}^{2} - {(1)}^{2} - {( \sqrt{2} )}^{2} \\ \\ \tt→ { \{1/2 \}}^{} - 1 - 2 \\ \\ \to \tt \frac{1 - 2 - 4}{2} = \frac{1 - 6}{2} = \frac{ - 5}{2} \\ \\ \boxed{\huge \to \: \boxed{\red{ \sf \: - 2.5}}} \: \: \: \: \: \: \: \: \: \small \boxed{ \green✓}$