Math, asked by darshan742005, 2 months ago

sin^2 60°+cos^2 62° =?​

Answers

Answered by chiggi2k03
1

Answer:

0.97

Step-by-step explanation:

The value of sin 60° = √3/2    and,

the value of cos 62° =  0.46947156          (by log table this value is calculated)

    now,

         sin^2 60°+cos^2 62° = ( √3/2 )^2  +   (0.469)^2

                                            =   3/4     +     0.220 (approx)

                                            = 0.97

So the answer of sin^2 60°+cos^2 62° = 0.97  

 plz mark this as brainliast.

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