Question

sin^2 63°+sin^2 27°/cos^2 17°+cos^2 73°

Answer 1

${sin}^{2} (90 - 27) + {sin}^{2} 27 = {cos}^{2} 27 + {sin}^{2} 27 = 1$

${cos}^{2} (90 - 73) + {cos}^{2} 73 = {sin}^{2} 73 + {cos}^{2} 73 = 1$

so,

$\frac{1}{1} = 1$

the answer is

${\red{\boxed{1}}}$

HOPE IT HELPS YOU ✨❤

Answer 2

ᎯᏁᏕᏯᎬᏒ

$\frac{ {sin}^{2} 63 ° + {sin}^{2} 27°}{ {cos}^{2}17° + {cos}^{2}73 ° }$

$\boxed{\red{{sin}^{2}(90 \degree \: - \theta)={cos}^{2} \theta }}$

$\boxed{ \red{ {cos }^{2}(90 \degree \: - \theta) ={sin}^{2} \theta }}$

$\frac{ sin² (90° - 63°)+ cos² 27°}{</p><p>cos(90° - 73°) + {cos }^{2} 73°}$

$\boxed{\red{{sin }^{2} \theta +{cos }^{2} \theta = 1 }}$

$\frac{ cos² \: 27° + sin² \: 27°}{</p><p>{sin }^{2} 73°+ {cos} ^{2} 73°}$

$\orange{\frac{1}{1} =1}$