sin^ 2 (630^ - theta)+cos^ 2 (4 50^ + theta)^ 2 =1
Answers
Answered by
1
(cos222+cos268sin222+sin268+sin263+cos63sin27)
={cos2(90−68)+cos268sin2(90−68)+sin268+sin263+cos63sin(90−63)}
={sin268+cos268cos268+sin268+sin263+cos63cos63}
=(1+sin263+cos263)
=1+1
=2
Similar questions