Math, asked by ishu212004, 10 months ago

sin^2 67°+ sin ^2 23° plzz solve it...​

Answers

Answered by Anonymous
5

★ SOLUTION:-

sin²67°+sin²23°

= sin²(90°-23°)+sin²23°

= cos²23°+sin²23°

= 1

please mark it BRAINLIEST ✌️

Answered by Anonymous
3

 \large \pink{ \underline{  \underline{ \sf \:    Answer : \:  \:  \: } }}

 \implies \sf { \sin }^{2}  \: 67\degree +  { \sin }^{2}  \: 23\degree  = 1

 \large \pink{ \underline{  \underline{ \sf \:Solution    : \:  \:  \: } }}

 \implies \sf { \sin }^{2}  \: 67\degree +  { \sin }^{2}  \: 23\degree  \\  \\ \implies \sf  { \sin }^{2}  \:  (90 - 23)\degree + { \sin }^{2}  \: 23\degree  \\  \\ \implies \sf  { \cos }^{2}  \: 23\degree + { \sin}^{2}  \: 23\degree \\  \\ \implies \sf  1

 \large \pink{ \underline{  \underline{ \sf \:Remmember   : \:  \:  \: } }}

  \sf\star \: \sin \: (90 -  \theta)  =  \cos  \theta \\  \\  \sf \star \:  \:  { \sin }^{2}  \theta +  { \cos }^{2}  \theta = 1

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