sin^2(π/8 + ∅/2) - sin^2(π/8 - ∅/2) = 1/✓2sin∅
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use rule of a^2-b^2 =a+b * a-b
then use sin c + sin d trigonometric identity
math can only be learnt by practice go solve
then use sin c + sin d trigonometric identity
math can only be learnt by practice go solve
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we know that sin2A-sin2B = sin (A+B)sin(A-B)π/8 + a/2+π/8 - a/2) sin(π/8 + a/2-π/8+ a/2)sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=sin(π/4) sin(a)=sin(=(1/ ) sina ...
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