Question

sin^2 A. tan^2 A
________ +1 = _________
cos^2 A. sin^2 A​

Answer 1

The left member can be writtten in this way:

(1)=2sinAcosA

The right member can be written in this way:

(2)=2tanA1+tan2A=2⋅sinAcosA1+sin2Acos2a=2⋅sinAcosAcos2A+sin2Acos2A=

=2⋅sinAcosA⋅cos2A1=2sinAcosA=(1).

Brainiest pls....